-4t^2+27t+2=0

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Solution for -4t^2+27t+2=0 equation:



-4t^2+27t+2=0
a = -4; b = 27; c = +2;
Δ = b2-4ac
Δ = 272-4·(-4)·2
Δ = 761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{761}}{2*-4}=\frac{-27-\sqrt{761}}{-8} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{761}}{2*-4}=\frac{-27+\sqrt{761}}{-8} $

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